Project Euler Problem #6 - Sum Square Difference (in Java)

public class Problem_6_Sum_Square_Difference {

    /*
        The sum of the squares of the first ten natural numbers is,
        12 + 22 + ... + 102 = 385
		
        The square of the sum of the first ten natural numbers is,
        (1 + 2 + ... + 10)2 = 552 = 3025
		
        Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 - 385 = 2640.

        Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
    */
	
    public static void main (String[] args) {
		
        int sumSquares = 0, sum = 0, difference = 0;
		
        for (int i = 1; i <= 100; i++) {
            sum += i;
            sumSquares += (int)Math.pow(i, 2);
        }
		
        difference = (int)Math.pow(sum, 2) - sumSquares;
        System.out.println(difference);
    }
}

              Created: February 10, 2014
Completed in full by: Michael Yaworski